Chapter 11 homework, part 1

16, 19, 20, 25, 27, 32, 33, 34, 35, 39, 40

19. One way to approach this problem is to compare the molecular formulas for the compounds. Compounds with the same molecular formulas but different structures are isomers. The molecular formulas are:

(a) C3H6O (b) C3H6O (c) C3H8O (d) C4H8O (e) C3H6O2 (f) C3H6O2 (g) C3H8O2

Therefore, (a) and (b) are isomers, as are (e) and (f)

25. (a) normal (b) normal (c) branched (d) branched (e) normal (f) branched

27. (a) these are the same compound (b) these are structural isomers (c) these are the same compound (d) these are structural isomers.

33. (a) 3-ethylhexane (b) 3-ethyl-4-methylhexane (c) 4-t-butyl-5-isopropyloctane (d) 5-isopropyl-2-methyloctane (e) 4-isopropyl-4-propylheptane

35.

 

39. (a) The name has numbers for two branches but only one branch is named. Presumably the name should be 2,2-dimethylbutane. (b) The numbering did not start at the "short end". The name should be 4-ethyl-3-methylheptane (c) The longest chain was not used. A "branch" on Carbon #1 extends the chain. The name should be 5-ethyl-2-methylheptane.

 

Chapter 11 Homework, part 2

43, 44, 46, 47, 50, 52, 58, 59, 60

43. (a) 1-ethyl-1-methylcyclopentane (b) t-butylcyclohexane (c) 2-chloro-1,3-dimethylcyclopentane (d) 1-ethyl-2-propylcyclopropane

47. Five structural isomers of C5H10 are shown below:

59. (a) 2 C2H6 + 7 O2 --> 4 CO2 + 6 H2O

(b) C5H12 + 8 O2 --> 5 CO2 + 6 H2O

(c) 2 C5H10 + 15 O2 --> 10 CO2 + 10 H2O